Question

Determine the vertex and axis of symmetry of y=x2−10x+3
𝑦
=
𝑥
2
−
10
𝑥
+
3
.(1 point)

Answer 1

For y = x^2 − 10x + 3:

Vertex: x = −b/(2a) = −(−10)/(2·1) = 5.
y(5) = 5^2 − 10·5 + 3 = 25 − 50 + 3 = −22.

So the vertex is (5, −22) and the axis of symmetry is x = 5.