Question

Determine the zeros of the quadratic function y=−x2+16x−39
𝑦
=
−
𝑥
2
+
16
𝑥
−
39
. (When listing the smaller zero, remember that negative values are always smaller than positive values.)(1 point)

Answer 1

Solve -x^2 + 16x - 39 = 0 → multiply by -1: x^2 - 16x + 39 = 0.
Discriminant = 16^2 - 4·1·39 = 256 - 156 = 100, sqrt = 10.
x = (16 ± 10)/2 → x = 3 or x = 13.

Zeros: 3 and 13 (smaller zero = 3).