Question

Determine the zeros of the quadratic function y=x2+15x+36
𝑦
=
𝑥
2
+
15
𝑥
+
36
. (When listing the smaller zero, remember that negative values are always smaller than positive values.)(1 point)

Answer 1

Set y = 0: x^2 + 15x + 36 = 0.
Factor: (x + 3)(x + 12) = 0, so x = -3 or x = -12.

Smaller zero: -12; larger zero: -3.