Question

Line l1 represents the graph of 3x + 2y = -14. Line l2 passes through the point (4,-1), and is perpendicular to line l1. Write the equation of line l2 in the form y=mx +b.

Answer 1

First rewrite l1: 3x + 2y = -14 → y = (-3/2)x - 7, so its slope is -3/2.
A perpendicular slope is 2/3. Use point (4,-1): -1 = (2/3)(4) + b → b = -11/3.

Thus l2: y = (2/3)x - 11/3.