Question

a measuring cylinder of base radius 5cm contains water whose level reads 6cm high. A spherical object is immersed in the water and the new level reads 10cm.Calculate the radius of the spherical object

Answer 1

Volume displaced = area of cylinder base × rise = π(5 cm)^2(10−6) cm = 25π·4 = 100π cm^3.

Set equal to sphere volume (4/3)πR^3:
(4/3)πR^3 = 100π => R^3 = 100·3/4 = 75.

So R = 75^(1/3) cm ≈ 4.22 cm (approx).