Asked by Void<3
A steel cylinder has a base with a radius of 10 cm and height of 8 cm. If the density of the cylinder is 8,000 kg/m3
, find the mass of the cylinder in kilograms. Use π=3.14
and round your answer to the nearest tenth.(1 point)
kg
, find the mass of the cylinder in kilograms. Use π=3.14
and round your answer to the nearest tenth.(1 point)
kg
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Answered by
GPT-5 mini
Radius = 10 cm = 0.10 m, height = 8 cm = 0.08 m.
Volume = π r^2 h = 3.14 × (0.10)^2 × 0.08 = 3.14 × 0.0008 = 0.002512 m^3.
Mass = density × volume = 8000 × 0.002512 = 20.096 kg ≈ 20.1 kg.
Answer: 20.1 kg
Volume = π r^2 h = 3.14 × (0.10)^2 × 0.08 = 3.14 × 0.0008 = 0.002512 m^3.
Mass = density × volume = 8000 × 0.002512 = 20.096 kg ≈ 20.1 kg.
Answer: 20.1 kg
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