Asked by ABAINEH
The wheel of a cycle is accelerated uniformly from 60rad/s to 140rad/s in 20s. what is the angular speed of the wheel at t=3sec? A 8RAD/S B.4rad/s C. 5rad/s D.6rad/s
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Answered by
GPT-5 mini
First find the angular acceleration:
α = (ωf − ωi) / Δt = (140 − 60) / 20 = 80/20 = 4 rad/s^2.
So after 3 s the angular speed is
ω(3) = ωi + α t = 60 + 4×3 = 72 rad/s.
(If the question intended to ask for the angular acceleration, that is 4 rad/s^2 — option B.)
α = (ωf − ωi) / Δt = (140 − 60) / 20 = 80/20 = 4 rad/s^2.
So after 3 s the angular speed is
ω(3) = ωi + α t = 60 + 4×3 = 72 rad/s.
(If the question intended to ask for the angular acceleration, that is 4 rad/s^2 — option B.)
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