Question

The wheel of a cycle is accelerated uniformly from 60rad/s to 140rad/s in 20s. what is the angular speed of the wheel at t=3sec?

Answer 1

Angular acceleration α = (ω_final − ω_initial) / Δt = (140 − 60) / 20 = 80 / 20 = 4 rad/s².

Angular speed at t = 3 s: ω = ω_initial + α t = 60 + 4·3 = 72 rad/s.