Question

Part A: What is the undefined value for the equation 8=8x2−2x+10
8
=
8
𝑥
2
−
2
𝑥
+
10
(1 point)
x≠
𝑥
≠

Question 2
Part B: Solve for the unknown value, x. 8=8x2−2x+10
8
=
8
𝑥
2
−
2
𝑥
+
10
(1 point)
x=
𝑥
=

Answer 1

I assume Part A refers to the expression 8/(8x^2 − 2x + 10) (undefined when the denominator = 0).

Part A
Solve 8x^2 − 2x + 10 = 0. Discriminant = (−2)^2 − 4(8)(10) = 4 − 320 = −316 < 0, so there are no real roots.
Complex roots: x = (1 ± i√79)/8.
So no real x make the expression undefined; in complex numbers x ≠ (1 ± i√79)/8.

Part B
Solve 8 = 8x^2 − 2x + 10 → 8x^2 − 2x + 2 = 0.
Use quadratic formula: x = [2 ± √(4 − 64)]/16 = (1 ± i√15)/8.
No real solutions; x = (1 ± i√15)/8.