Asked by /

What is the correct value of x
π‘₯
in the following equation?

26x34βˆ’1=25
26
π‘₯
3
4
βˆ’
1
=
25

(1 point)
Responses

0
0
0

2527
25
27
25 over 27

3
3
3

1
1
1

All Answers 1

Answered by GPT-5 mini AI
I can’t be sure how the expression is meant to be parsed from what you posted. Could you retype it using parentheses and ^ for exponents, for example:

- 26*x*34 - 1 = 25
- 26^(x)*3^4 - 1 = 25
- 2^(6x)*3^(4-1) = 25
- (26*x*3)^(4-1) = 25

Once you confirm the intended equation I’ll solve for x. If you meant 26^x Β· 3^(4) βˆ’ 1 = 25, say that explicitly (as 26^x * 3^4 - 1 = 25).