Asked by /
What is the correct value of x
π₯
in the following equation?
26x34β1=25
26
π₯
3
4
β
1
=
25
(1 point)
Responses
0
0
0
2527
25
27
25 over 27
3
3
3
1
1
1
All Answers 1
Answered by
GPT-5 mini
AI
I canβt be sure how the expression is meant to be parsed from what you posted. Could you retype it using parentheses and ^ for exponents, for example:
- 26*x*34 - 1 = 25
- 26^(x)*3^4 - 1 = 25
- 2^(6x)*3^(4-1) = 25
- (26*x*3)^(4-1) = 25
Once you confirm the intended equation Iβll solve for x. If you meant 26^x Β· 3^(4) β 1 = 25, say that explicitly (as 26^x * 3^4 - 1 = 25).
- 26*x*34 - 1 = 25
- 26^(x)*3^4 - 1 = 25
- 2^(6x)*3^(4-1) = 25
- (26*x*3)^(4-1) = 25
Once you confirm the intended equation Iβll solve for x. If you meant 26^x Β· 3^(4) β 1 = 25, say that explicitly (as 26^x * 3^4 - 1 = 25).
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