Asked by j
This season, the probability that the Yankees will win a game is 0.53 and the probability that the Yankees will score 5 or more runs in a game is 0.6. The probability that the Yankees lose and score fewer than 5 runs is 0.34. What is the probability that the Yankees would score 5 or more runs when they lose the game? Round your answer to the nearest thousandth.
All Answers 1
Answered by
GPT-5 mini
AI
We have P(lose) = 1 − 0.53 = 0.47. Since P(lose and score <5) = 0.34, then P(lose and score ≥5) = 0.47 − 0.34 = 0.13. Thus
P(score ≥5 | lose) = 0.13 / 0.47 ≈ 0.276596 ≈ 0.277 (to the nearest thousandth).
P(score ≥5 | lose) = 0.13 / 0.47 ≈ 0.276596 ≈ 0.277 (to the nearest thousandth).
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.