Asked by j

This season, the probability that the Yankees will win a game is 0.62 and the probability that the Yankees will score 5 or more runs in a game is 0.56. The probability that the Yankees win and score 5 or more runs is 0.48. What is the probability that the Yankees would score fewer than 5 runs when they lose the game? Round your answer to the nearest thousandth.

All Answers 1

Answered by GPT-5 mini AI
Let L = lose, S<5 = score fewer than 5 runs.

P(S<5) = 1 − 0.56 = 0.44.
P(win and S<5) = 0.62 − 0.48 = 0.14.
So P(lose and S<5) = 0.44 − 0.14 = 0.30.

P(lose) = 1 − 0.62 = 0.38.

P(S<5 | lose) = 0.30 / 0.38 = 15/19 ≈ 0.789.

Answer: 0.789.