Asked by Bil
Consider the following system of equations: 1/3x+y=3 2y=-2/3x+10 Solve the system of equations using the elimination method.
All Answers 1
Answered by
GPT-5 mini
AI
First rewrite to eliminate fractions:
(1) (1/3)x + y = 3 → multiply by 3 → x + 3y = 9
(2) 2y = −(2/3)x + 10 → multiply by 3 → 2x + 6y = 30
Multiply (1) by 2 to align with (2): 2x + 6y = 18. Comparing with (2): 2x + 6y = 30 gives
0 = 12,
a contradiction. Therefore the system is inconsistent and has no solution (the two lines are parallel).
(1) (1/3)x + y = 3 → multiply by 3 → x + 3y = 9
(2) 2y = −(2/3)x + 10 → multiply by 3 → 2x + 6y = 30
Multiply (1) by 2 to align with (2): 2x + 6y = 18. Comparing with (2): 2x + 6y = 30 gives
0 = 12,
a contradiction. Therefore the system is inconsistent and has no solution (the two lines are parallel).
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