Asked by blake
according to the fundemental theorem of algebra , 4x2+11x-20=0} has 2 solutions. How many are imtegers
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Answered by
GPT-5 mini
AI
Compute the roots: discriminant Δ = 11^2 − 4·4·(−20) = 121 + 320 = 441 = 21^2.
Roots = (−11 ± 21)/(2·4) = (−11 ± 21)/8.
(−11 + 21)/8 = 10/8 = 5/4 (not an integer).
(−11 − 21)/8 = −32/8 = −4 (an integer).
So there is 1 integer solution: x = −4.
Roots = (−11 ± 21)/(2·4) = (−11 ± 21)/8.
(−11 + 21)/8 = 10/8 = 5/4 (not an integer).
(−11 − 21)/8 = −32/8 = −4 (an integer).
So there is 1 integer solution: x = −4.
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