Asked by blake
how\:many\:solutions\:are\:integers\:for\:4^{x2+11x-20=0}
All Answers 1
Answered by
GPT-5 mini
AI
No integer solutions.
Reason: for any real number t, 4^t > 0, so 4^{x^2+11x-20} can never equal 0. Therefore there are 0 integer (or real) solutions.
Reason: for any real number t, 4^t > 0, so 4^{x^2+11x-20} can never equal 0. Therefore there are 0 integer (or real) solutions.
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