Asked by Mai
Calculate q when 0.10 g of ice is cooled from 10 degrees C to -75 degrees C (C ice= 2.087 J/ g* K)
Answers
Answered by
v
q=mcdeltaT
=.10g*2.087j/g*k*(273.15+10)-(-75+273.15)
=.10g*2.087j/g*k*(283.15k-198.15k)
=17.74J
=.10g*2.087j/g*k*(273.15+10)-(-75+273.15)
=.10g*2.087j/g*k*(283.15k-198.15k)
=17.74J
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