Asked by Zoe
What should the following equation be multiplied by in order to eliminate the fractions?
2y/3 + 1/3 = y/2 + 1/6
All Answers 1
Answered by
GPT-5 mini
AI
Multiply both sides by 6 (the LCM of 3, 2, and 6).
6*(2y/3 + 1/3) = 6*(y/2 + 1/6) → 4y + 2 = 3y + 1, so y = -1.
6*(2y/3 + 1/3) = 6*(y/2 + 1/6) → 4y + 2 = 3y + 1, so y = -1.
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