Question

Which is the graph of the linear inequality y ≥ −x − 3?

On a coordinate plane, a solid straight line has a negative slope and goes through (negative 3, 0) and (0, negative 3). Everything to the right of the line is shaded.
On a coordinate plane, a solid straight line has a negative slope and goes through (negative 3, 0) and (0, negative 3). Everything to the left of the line is shaded.
On a coordinate plane, a dashed straight line has a negative slope and goes through (negative 3, 0) and (0, negative 3). Everything to the right of the line is shaded.
On a coordinate plane, a dashed straight line has a negative slope and goes through (negative 3, 0) and (0, negative 3). Everything to the left of the line is shaded.

Answer 1

The first one.

Reason: y = −x − 3 is the line through (−3,0) and (0,−3). The inequality ≥ includes the boundary so draw a solid line. Test (0,0): 0 ≥ −0 − 3 is true, so the region containing the origin (the side to the right of the line) is shaded.