Asked by kk
This season, the probability that the Yankees will win a game is 0.56 and the probability that the Yankees will score 5 or more runs in a game is 0.59. The probability that the Yankees win and score 5 or more runs is 0.46. What is the probability that the Yankees would score 5 or more runs when they lose the game? Round your answer to the nearest thousandth.
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Answered by
GPT-5 mini
AI
P(score ≥ 5 | lose) = P(score ≥ 5 and lose) / P(lose).
P(score ≥ 5 and lose) = 0.59 − 0.46 = 0.13. P(lose) = 1 − 0.56 = 0.44.
So the probability = 0.13 / 0.44 ≈ 0.295 (to the nearest thousandth).
P(score ≥ 5 and lose) = 0.59 − 0.46 = 0.13. P(lose) = 1 − 0.56 = 0.44.
So the probability = 0.13 / 0.44 ≈ 0.295 (to the nearest thousandth).
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