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Which of the following uses the substitution method to solve linear-quadratic system y = x^2 - 4x + 8, y = 3x - 4? (1 point)
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Substitute y = 3x − 4 into y = x^2 − 4x + 8:
x^2 − 4x + 8 = 3x − 4
x^2 − 7x + 12 = 0
(x − 3)(x − 4) = 0 → x = 3 or x = 4
Find y from y = 3x − 4:
x = 3 → y = 5
x = 4 → y = 8
Solutions: (3, 5) and (4, 8).
x^2 − 4x + 8 = 3x − 4
x^2 − 7x + 12 = 0
(x − 3)(x − 4) = 0 → x = 3 or x = 4
Find y from y = 3x − 4:
x = 3 → y = 5
x = 4 → y = 8
Solutions: (3, 5) and (4, 8).
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