Asked by jk
Which statement describes the behavior of the graph of the function shown at the vertical asymptotes?
As x approaches -7 from the left, y approaches ∞.
As x approaches -7 from the right, y approaches -∞.
As x approaches 7 from the left, y approaches –∞.
As x approaches 7 from the right, y approaches –∞.
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have the graph you mention, so I can’t pick which statement is true. Can you upload the graph image or describe the behavior near x = −7 and x = 7 (what the curve does just left and just right of those x-values)?
If you want to decide it yourself, here are two quick ways:
1) From the graph: look at points just to the left and just to the right of each vertical asymptote.
- If y goes up without bound, the limit is +∞.
- If y goes down without bound, the limit is −∞.
- Record the left- and right-hand limits at x = −7 and x = 7 and match them to the statements.
2) From an equation f(x) = N(x)/D(x): factor D(x). For an asymptote at x = a, check the sign of N(x) and D(x) for x values slightly less than a and slightly greater than a. The sign of f(x) determines whether it goes to +∞ or −∞ on each side (positive → +∞, negative → −∞). If a factor in D has even multiplicity the sign of D doesn’t change crossing a, if odd multiplicity it does.
If you send the graph or the function I’ll pick the correct statement.
If you want to decide it yourself, here are two quick ways:
1) From the graph: look at points just to the left and just to the right of each vertical asymptote.
- If y goes up without bound, the limit is +∞.
- If y goes down without bound, the limit is −∞.
- Record the left- and right-hand limits at x = −7 and x = 7 and match them to the statements.
2) From an equation f(x) = N(x)/D(x): factor D(x). For an asymptote at x = a, check the sign of N(x) and D(x) for x values slightly less than a and slightly greater than a. The sign of f(x) determines whether it goes to +∞ or −∞ on each side (positive → +∞, negative → −∞). If a factor in D has even multiplicity the sign of D doesn’t change crossing a, if odd multiplicity it does.
If you send the graph or the function I’ll pick the correct statement.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.