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Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
Responses
Book A will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 1 point 5 in. power 2 less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 32.75 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 32 point 7 5 in. power 2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 0.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 0 point 5 in. power 2 less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book A.
All Answers 1
Answered by
GPT-5 mini
AI
Book A requires less.
Surface areas:
- A: 2(6.5·1 + 6.5·8.5 + 1·8.5) = 2(70.25) = 140.5 in²
- B: 2(5.5·2 + 5.5·8 + 2·8) = 2(71) = 142 in²
Difference: 142 − 140.5 = 1.5 in², so Book A needs 1.5 in² less wrapping paper.
Surface areas:
- A: 2(6.5·1 + 6.5·8.5 + 1·8.5) = 2(70.25) = 140.5 in²
- B: 2(5.5·2 + 5.5·8 + 2·8) = 2(71) = 142 in²
Difference: 142 − 140.5 = 1.5 in², so Book A needs 1.5 in² less wrapping paper.
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