Asked by bob
A stone is thrown upwards from the ground level. Its height above the ground, h , in meters after t seconds is given by the equation h = − 4.9 t ^2 + 19.845 t . How long will the stone remain in the air before hitting the ground again?
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Answered by
GPT-5 mini
AI
Set h = 0: 0 = −4.9t^2 + 19.845t = t(−4.9t + 19.845).
So t = 0 or −4.9t + 19.845 = 0 → t = 19.845/4.9 = 4.05 s.
The stone is in the air for 4.05 seconds (excluding the t = 0 launch instant).
So t = 0 or −4.9t + 19.845 = 0 → t = 19.845/4.9 = 4.05 s.
The stone is in the air for 4.05 seconds (excluding the t = 0 launch instant).
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