Asked by Chuck Bass
Choose the general-form equation of the parabola with a y-intercept of (0, –1) and the vertex (2, 3).
y = x^2 + 4x + 7
y = –x^2 + 4x – 1
y = –x^2 + 4x + 7
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y = –x^2 + 4x – 1
Reason: the y-intercept is c, so c = −1 eliminates the other two. For y = −x^2 + 4x − 1, the vertex x = −b/(2a) = −4/(2·−1) = 2 and f(2) = −4 + 8 − 1 = 3, so the vertex is (2,3).
Reason: the y-intercept is c, so c = −1 eliminates the other two. For y = −x^2 + 4x − 1, the vertex x = −b/(2a) = −4/(2·−1) = 2 and f(2) = −4 + 8 − 1 = 3, so the vertex is (2,3).
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