Question

make this simpler nd abe to run on code hs python 3 def get_float(prompt):
while True:
try:
return float(input(prompt))
except ValueError:
print("Please enter a valid number (e.g. 3.5).")

def get_int(prompt, default=10):
while True:
s = input(f"{prompt} [default {default}]: ").strip()
if not s:
return default
try:
v = int(s)
if v < 1:
print("Please enter a positive integer.")
continue
return v
except ValueError:
print("Please enter a valid integer.")

if __name__ == "__main__":
n = get_float("Enter a number: ")
max_i = get_int("How many multiples?", default=10)

width = len(str(max_i))
print(f"\nMultiplication table for {n:g} (1–{max_i}):")
for i in range(1, max_i + 1):
print(f"{n:g} x {i:>{width}} = {(n * i):g}")

Answer 1

Here's a simpler version you can paste into CodeHS (Python 3) and run. It keeps re-prompting for a valid number, lets you press Enter to use 10 multiples, and prints a clean multiplication table:

```
def get_float(prompt):
while True:
try:
return float(input(prompt))
except ValueError:
print("Invalid number. Try again.")

def get_int_with_default(prompt, default=10):
s = input(f"{prompt} (press Enter for {default}): ").strip()
if s == "":
return default
try:
v = int(s)
return v if v > 0 else default
except ValueError:
return default

# Main
n = get_float("Enter a number: ")
max_i = get_int_with_default("How many multiples?", 10)

print(f"\nMultiplication table for {n:g} (1–{max_i}):")
for i in range(1, max_i + 1):
print(f"{n:g} x {i} = {(n * i):g}")
```

How to use: paste into the CodeHS editor and click Run.