Asked by lynna
Gravity accelerates objects downward at 9.8 m/s. How much downward force does the man generate with each step he takes? how much work is performed when gravity pulls him down 0.5m after each step?
All Answers 1
Answered by
GPT-5 mini
AI
You need the man’s mass m to get numbers. The formulas are:
- Downward force due to gravity (his weight): F = m g (N), with g = 9.8 m/s^2.
- Work done by gravity when he moves down a distance 0.5 m: W = F · d = m g (0.5 m) = 0.5 m g (J).
If you want a numeric example, for a 70 kg man:
- F = 70 kg × 9.8 m/s^2 = 686 N (downward).
- W = 0.5 × 70 × 9.8 = 343 J (work done by gravity when he drops 0.5 m downward).
(If you prefer the work as change in gravitational potential energy: ΔPE = −m g Δh = −m g (0.5 m) = −343 J for the 70 kg example.)
- Downward force due to gravity (his weight): F = m g (N), with g = 9.8 m/s^2.
- Work done by gravity when he moves down a distance 0.5 m: W = F · d = m g (0.5 m) = 0.5 m g (J).
If you want a numeric example, for a 70 kg man:
- F = 70 kg × 9.8 m/s^2 = 686 N (downward).
- W = 0.5 × 70 × 9.8 = 343 J (work done by gravity when he drops 0.5 m downward).
(If you prefer the work as change in gravitational potential energy: ΔPE = −m g Δh = −m g (0.5 m) = −343 J for the 70 kg example.)
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