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How do you find unpaired electrons in a metal ion in CuSO4·5H20?
14 years ago

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DrBob222
You write the electron structure like this.
1s2 2s2 2p6 3s2 3p6 3d10 4s1 is the neutral Cu atom.
Remove the two outside electrons to make the Cu^+2 ion. That leaves us with
3d9 as the outside and since that is an odd number, one electron must be unpaired. And you will note that many Cu(II) compounds are colored.
14 years ago

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