Question

Which is the graph of f(x) = one-fourth(4)x?

On a coordinate plane, an exponential function approaches y = 0 in quadrant 1. It curves up to the left and goes through points (2, 1) and (0, 4).

On a coordinate plane, an exponential function approaches y = 0 in quadrant 1. It curves up to the left and goes through points (1, 1) and (0, 4).

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and goes through points (3, 2) and (4, 4).

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and goes through points (1, 1) and (2, 4).

Answer 1

The fourth graph.

Reason: f(x) = (1/4)·4^x = 4^{x-1}. So f(1) = (1/4)·4 = 1 and f(2) = (1/4)·16 = 4, and the horizontal asymptote is y = 0 (approached as x → −∞, i.e. in quadrant II). These match the fourth option.