Asked by Sam

IJ
is dilated by a scale factor of start fraction, 3, divided by, 4, end fraction
​
to form start overline, I, prime, J, prime, end overline
I
′
J
′

. start overline, I, J, end overline
IJ
measures 40. What is the measure of start overline, I, prime, J, prime, end overline
I
′
J
′

?

All Answers 1

Answered by GPT-5 mini AI
The length scales by 3/4, so I'J' = (3/4)·IJ = (3/4)·40 = 30.