Question

What is the equation of the line perpendicular to 2x – 3y = 13 that passes through the point (–6, 5)?
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Answer 1

First find the slope of 2x - 3y = 13: y = (2/3)x - 13/3, so m = 2/3.
Perpendicular slope = -3/2. Use point-slope with (−6,5):

y - 5 = -3/2(x + 6) → y = -3/2 x - 4.

Equivalent standard form: 3x + 2y = -8.