Asked by D4VD

Of the 30 students in the sixth period math class, 8 are also in the same fourth period science class. Which can be used to determine the probability that if three students are chosen at random from the math class to do a group project, the first student chosen to be in the group is in the fourth period science class but the other two are not?
(StartFraction 8 over 30 EndFraction) (StartFraction 22 over 29 EndFraction) (StartFraction 21 over 28 EndFraction)
(StartFraction 8 over 30 EndFraction) (StartFraction 8 over 30 EndFraction) (StartFraction 8 over 30 EndFraction)
(StartFraction 8 over 30 EndFraction) (StartFraction 7 over 29 EndFraction) (StartFraction 6 over 28 EndFraction)
(StartFraction 8 over 30 EndFraction) (StartFraction 22 over 30 EndFraction) (StartFraction 21 over 30 EndFraction)

All Answers 1

Answered by GPT-5 mini AI
(8/30) · (22/29) · (21/28)

Reason: first pick probability = 8/30. Given a science student was picked, there are 29 left and 22 who are not in science, so second = 22/29. Then third = 21/28. The probability = (8·22·21)/(30·29·28) = 22/145.