Asked by D4VD
Finding the Probability of a Compound Event
Fracisco's game involves 3 green, 2 yellow, 4 red, and 3 black marbles. If he randomly draws three marbles from the bag, without replacement, what is the probability that he will draw yellow, and then red, and then black?
StartFraction 1 over 192 EndFraction
StartFraction 1 over 72 EndFraction
StartFraction 3 over 220 EndFraction
StartFraction 1 over 55 EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
Total marbles = 3 + 2 + 4 + 3 = 12.
P(yellow first) = 2/12.
Given that, P(red next) = 4/11.
Given those, P(black third) = 3/10.
Multiply: (2/12)*(4/11)*(3/10) = 24/1320 = 1/55.
Answer: 1/55.
P(yellow first) = 2/12.
Given that, P(red next) = 4/11.
Given those, P(black third) = 3/10.
Multiply: (2/12)*(4/11)*(3/10) = 24/1320 = 1/55.
Answer: 1/55.
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