Question

Finding Probabilities of Compound Events
A regular deck of cards has 52 cards with 4 aces. Carl asked a friend to pick a card from the deck three times, replacing the card each time. His friend picked three aces. Which expression will give the probability of that event?
(StartFraction 4 over 52 EndFraction) (StartFraction 4 over 52 EndFraction) (StartFraction 4 over 52 EndFraction)
(StartFraction 1 over 52 EndFraction) (StartFraction 1 over 51 EndFraction) (StartFraction 1 over 50 EndFraction)
(StartFraction 4 over 52 EndFraction) (StartFraction 4 over 51 EndFraction) (StartFraction 4 over 50 EndFraction)
(StartFraction 4 over 52 EndFraction) (StartFraction 3 over 51 EndFraction) (StartFraction 2 over 50 EndFraction)

Answer 1

Because the card is replaced each time the draws are independent and each draw has probability 4/52 = 1/13 of an ace. So the probability is (4/52)^3 = (1/13)^3 = 1/2197. The correct expression is (4/52)(4/52)(4/52).