Question

Consider the graph of the quadratic function y = 2x2 – 4x + 2.


How many zeros does the function have?

Answer 1

Compute the discriminant: Δ = b^2 − 4ac = (−4)^2 − 4(2)(2) = 16 − 16 = 0.
Since Δ = 0, the quadratic has one real (double) root. The zero is at x = −b/(2a) = 4/(4) = 1.