Question

The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) using a point and the slope. Which point did Harold use?

(7, 3)
(0, 7)
(7, 0)
(3, 7)

Answer 1

Match y = 3(x − 7) to y − y1 = m(x − x1). It is y − 0 = 3(x − 7), so y1 = 0 and x1 = 7. The point is (7, 0).