Question

On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). The dashed-line parabola, labeled g of x, goes through (negative 6, 10), has a vertex at (negative 4, 6), and goes through (negative 2, 10).
What is the equation of the translated function, g(x), if
f(x) = x2?

g(x) = (x – 4)2 + 6
g(x) = (x + 6)2 – 4
g(x) = (x – 6)2 – 4
g(x) = (x + 4)2 + 6

Answer 1

g(x) = (x + 4)^2 + 6

Reason: vertex at (-4,6) gives g(x)=a(x+4)^2+6. Using point (-6,10): 4a+6=10 → a=1, so g(x)=(x+4)^2+6.