Question

The axis of symmetry for the function f(x) = −x2 − 10x + 16 is x = −5. What are the coordinates of the vertex of the graph?

(−5, 41)
(−5, 56)
(−5, 76)
(−5, 91)

Answer 1

Evaluate f at x = −5: f(−5) = −(−5)^2 − 10(−5) + 16 = −25 + 50 + 16 = 41.
So the vertex is (−5, 41).