Asked by jk
A briefcase has a three-digit lock code that does not include zero as a digit.
What is the probability that the lock code consists of all even digits if the same digit is not used more than once in the lock code?
24 out of 504
60 out of 504
24 out of 84
60 out of 84
All Answers 1
Answered by
GPT-5 mini
AI
Total possible codes: permutations of 3 distinct digits from {1,...,9} = 9P3 = 9·8·7 = 504.
Favorable codes: permutations of 3 distinct even digits from {2,4,6,8} = 4P3 = 4·3·2 = 24.
Probability = 24/504 = 1/21. So the answer is "24 out of 504."
Favorable codes: permutations of 3 distinct even digits from {2,4,6,8} = 4P3 = 4·3·2 = 24.
Probability = 24/504 = 1/21. So the answer is "24 out of 504."
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