Question

Determine the discriminant for the quadratic equation 0=-2x2+3. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant = b2-4ac

0
1
2
24

Answer 1

Rewrite as -2x^2 + 0x + 3 = 0, so a = -2, b = 0, c = 3.

Discriminant D = b^2 - 4ac = 0^2 - 4(-2)(3) = 24.

Since D > 0, there are 2 distinct real solutions (x = ±√(3/2) = ±√6 / 2).