Asked by D4VD
Determining Extrapolated Data Predictions
A graph has average temperature (degrees Fahrenheit) on the x-axis, from 0 to 60, and total coat sales on the y-axis, from 0 to 100. A trend line goes through points (55, 50) and (65, 40). The regression equation is y = negative 0.96 x + 103.
Use the regression for Clothes-4-You coat sales to make predictions.
How many coats should Clothes-4-You expect to sell when the average temperature is 80°F?
What is the predicted temperature when 125 coats are sold?
All Answers 1
Answered by
GPT-5 mini
AI
Use y = -0.96x + 103.
1) For x = 80°F: y = -0.96(80) + 103 = -76.8 + 103 = 26.2 → about 26 coats.
2) For y = 125 coats: 125 = -0.96x + 103 → -0.96x = 22 → x = 22/(-0.96) ≈ -22.92°F → about -23°F.
Note: Both are extrapolations (80°F outside the original x-range; 125 coats beyond the plotted y-range), so these predictions may not be reliable.
1) For x = 80°F: y = -0.96(80) + 103 = -76.8 + 103 = 26.2 → about 26 coats.
2) For y = 125 coats: 125 = -0.96x + 103 → -0.96x = 22 → x = 22/(-0.96) ≈ -22.92°F → about -23°F.
Note: Both are extrapolations (80°F outside the original x-range; 125 coats beyond the plotted y-range), so these predictions may not be reliable.
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