Asked by MATH HELP!
y= cot^2(sin(theta))
find dy/dx
For some reason i can never get these right! I hope someone that is on can help me with this
find dy/dx
For some reason i can never get these right! I hope someone that is on can help me with this
Answers
Answered by
Oswaldo
=(2)(cot(sin(theta)))(-csc^2(sin (theta)))(cos(theta))
= 2 cos(theta)(cot(sin(theta)))(csc^2(sin(theta))
= 2 cos(theta)(cot(sin(theta)))(csc^2(sin(theta))
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