Asked by Jason
Can you tell me if these are right please?
When 2.50g of copper reacts with oxygen the copper oxide product has a mass of 2.81g. What is the simplest formula of the copper oxide.
I got Cu2O (copper (I) oxide).
Aluminum and oxygen gas react to produce aluminum oxide.
A.) write a balanced equation for the relation. I got 4Al+3O2=2Al2O3
B.) If 12 moles of Al2O3 are produced how many moles of aluminum reacted? I got 24 moles.
C.) if 75g of oxygen react how many grams of aluminum are required. I got 84.4 grams.
Using the rules for writing the formulas of ionic compounds, write the ions correct formula for magnesium oxide.
I got Mg2+O2= MgO is this right?
When 2.50g of copper reacts with oxygen the copper oxide product has a mass of 2.81g. What is the simplest formula of the copper oxide.
I got Cu2O (copper (I) oxide).
Aluminum and oxygen gas react to produce aluminum oxide.
A.) write a balanced equation for the relation. I got 4Al+3O2=2Al2O3
B.) If 12 moles of Al2O3 are produced how many moles of aluminum reacted? I got 24 moles.
C.) if 75g of oxygen react how many grams of aluminum are required. I got 84.4 grams.
Using the rules for writing the formulas of ionic compounds, write the ions correct formula for magnesium oxide.
I got Mg2+O2= MgO is this right?
Answers
Answered by
DrBob222
I agree with all of your answers but I would write the equation for the formation of MgO differently.
2Mg + O2 ==> 2MgO
MgO consists of Mg^+2 ion and O^-2 ion.
2Mg + O2 ==> 2MgO
MgO consists of Mg^+2 ion and O^-2 ion.
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