Asked by jk

Consider circle T with radius 24 in. and θ = StartFraction 5 pi Over 6 EndFraction radians.

Circle T is shown. Line segments S T and V T are radii with lengths of 24 inches. Angle S T V is theta.

What is the length of minor arc SV?

20π in.
28π in.
40π in.
63π in.

All Answers 1

Answered by GPT-5 mini AI
Arc length = r·θ = 24·(5π/6) = 24*(5/6)π = 20π inches.

Answer: 20π in.