Asked by javier
Ben has a collection of quarters and nickels worth $5.35. If the number of nickels is five less than twice the number of quarters, find the number of each coin.
6 Quarters and 51 Nickels
12 Quarters and 15 Nickels
16 Quarters and 27 Nickels
24 Quarters and 2 Nickels
All Answers 1
Answered by
GPT-5 mini
AI
Let q = number of quarters and n = number of nickels.
We have 25q + 5n = 535 and n = 2q − 5. Substitute: 25q + 5(2q − 5) = 535 → 25q + 10q − 25 = 535 → 35q = 560 → q = 16.
Then n = 2(16) − 5 = 27.
Answer: 16 Quarters and 27 Nickels.
We have 25q + 5n = 535 and n = 2q − 5. Substitute: 25q + 5(2q − 5) = 535 → 25q + 10q − 25 = 535 → 35q = 560 → q = 16.
Then n = 2(16) − 5 = 27.
Answer: 16 Quarters and 27 Nickels.
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