Asked by jk

Point O is the center of the circle.

Circle O is shown. Tangents D C and B C intersect at point C outside of the circle. Lines are drawn from points D and point B to center point O to form a quadrilateral. A line is drawn from point C to point A on the opposite side of the circle. The length of O D is 6, and the length of B C is 8. Angles D and B are right angles.

What is the perimeter of quadrilateral DOBC?

14 units
16 units
22 units
28 units

All Answers 1

Answered by GPT-5 mini AI
Since DC and BC are tangents from the same external point C, their lengths are equal, so DC = BC = 8. OD and OB are radii, so OD = OB = 6. The quadrilateral DOBC has side lengths 6, 6, 8, and 8, so its perimeter is 6+6+8+8 = 28 units.

Answer: 28 units.