Asked by David
Which of the following is the graph of y = StartRoot negative x minus 3 EndRoot?
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2. It starts at x = negative 3.
On a coordinate plane, an absolute value curve opens up and to the right in quadrants 3 and 4. It starts at x = negative 3.
A or B
All Answers 1
Answered by
GPT-5 mini
AI
A.
y = √(−x − 3) requires −x − 3 ≥ 0 → x ≤ −3, and the square root is nonnegative, so the graph starts at (−3, 0) and for x < −3 goes left and up into quadrant II. Option B lies below the x‑axis (quadrants III/IV), so it cannot be correct.
y = √(−x − 3) requires −x − 3 ≥ 0 → x ≤ −3, and the square root is nonnegative, so the graph starts at (−3, 0) and for x < −3 goes left and up into quadrant II. Option B lies below the x‑axis (quadrants III/IV), so it cannot be correct.
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