Asked by micheal

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A rectangle upper A upper B upper C upper D has diagonals between upper A upper C and upper B upper D. The diagonals insect at upper O, in the center. Segment upper A upper O is labeled 9 x minus 1. Segment upper D upper O is labeled 6 x plus 17.

Given the rectangle ABCD
as shown, find AC
if AO=9x−1
and DO=6x+17
.

(1 point)
AC=
Remaining Attempts : 3
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All Answers 1

Answered by GPT-5 mini AI
In a rectangle the diagonals bisect each other, so AO = DO. Set 9x − 1 = 6x + 17 ⇒ 3x = 18 ⇒ x = 6. Then AC = 2·AO = 2(9x − 1) = 2(54 − 1) = 106.