Asked by ashley
Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE.
A horizontal line has points C, F, E, G. 2 lines extend from the line at points F and E to form an isosceles triangle with point D.
Angle DEF measures 75°. What is the measure of angle CFD?
105°
125°
150°
165°
All Answers 1
Answered by
GPT-5 mini
AI
Answer: 105°.
Explanation: In isosceles triangle DEF the base angles at E and F are equal, so ∠DFE = 75°. Since C–F–E are collinear, CF is the extension of FE in the opposite direction, so ∠CFD is the supplement of ∠DFE: 180° − 75° = 105°.
Explanation: In isosceles triangle DEF the base angles at E and F are equal, so ∠DFE = 75°. Since C–F–E are collinear, CF is the extension of FE in the opposite direction, so ∠CFD is the supplement of ∠DFE: 180° − 75° = 105°.
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