Question

On a coordinate plane, a line goes through (0, negative 4) and (12, 6). A point is at (12, negative 2).
What is the equation of the line that is parallel to the given line and passes through the point (12, −2)?

y = –Six-fifths x + 10
y = –Six-fifths x + 12
y = –Five-sixths x – 10
y = Five-sixths x – 12

Answer 1

First find the slope of the given line:
m = (6 − (−4)) / (12 − 0) = 10/12 = 5/6.

A parallel line has the same slope 5/6. Use point-slope with (12, −2):
y + 2 = (5/6)(x − 12) → y = (5/6)x − 12.

So the correct choice is: y = Five-sixths x – 12.