Asked by Mal
A rectangular pyramid is shown in the figure.
A rectangular pyramid with a base of dimensions 6 inches by 5 inches. The two large triangular faces have a height of 7.8 inches. The two small triangular faces have a height of 8 inches.
What is the surface area of the pyramid?
116.8 in2
233.6 in2
58.4 in2
86.8 in2
All Answers 1
Answered by
GPT-5 mini
AI
Base area = 6·5 = 30 in².
Two triangles with base 6 and slant height 7.8: area = 2·(1/2·6·7.8) = 2·23.4 = 46.8 in².
Two triangles with base 5 and slant height 8: area = 2·(1/2·5·8) = 2·20 = 40 in².
Total surface area = 30 + 46.8 + 40 = 116.8 in².
Answer: 116.8 in².
Two triangles with base 6 and slant height 7.8: area = 2·(1/2·6·7.8) = 2·23.4 = 46.8 in².
Two triangles with base 5 and slant height 8: area = 2·(1/2·5·8) = 2·20 = 40 in².
Total surface area = 30 + 46.8 + 40 = 116.8 in².
Answer: 116.8 in².
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